question about exercise 5.16 in the book (p.179) #246
fujiehuang
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We don't have a solution set. The key steps in the proof are showing that the first n-1 columns are linearly independent. This comes from the unreduced upper Hessenberg shape of the matrix. Assume that there is a non-trivial vector in the null space of the first n-1 columns, and you will reach a contradiction. Since the matrix is singular, the last column must be a linear combination of the previous n-1 columns. This implies that the last row of R is 0. Hope this helps. |
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Is there a quick explanation for the exercise 5.16 (p. 179 in the book)? I'm having a hard time proving it. Or is there a reference?
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